حل تشریحی سوال شماره 169 ریاضی (تبریز)

$\left[\begin{array}{c}2\\ -3\end{array}\right]+3\vec{X}=2i+6j=\left[\begin{array}{c}2\\ 0\end{array}\right]+\left[\begin{array}{c}0\\ 6\end{array}\right]=\left[\begin{array}{c}2\\ 6\end{array}\right](0/25)$

$\left[\begin{array}{c}2\\ -3\end{array}\right]+3\vec{X}=\left[\begin{array}{c}2\\ 6\end{array}\right]\Rightarrow 3\vec{X}=\underset{\begin{array}{c}\\ (0/25)\end{array}}{\left[\begin{array}{c}2\\ 6\end{array}\right]-\left[\begin{array}{c}2\\ -3\end{array}\right]=\left[\begin{array}{c}2\\ 6\end{array}\right]+\left[\begin{array}{c}-2\\ +3\end{array}\right]}=\left[\begin{array}{c}0\\ 9\end{array}\right](0/25)$

$3\vec{X}=\left[\begin{array}{c}0\\ 9\end{array}\right]\Rightarrow \vec{X}=\left[\begin{array}{c}0\\ 3\end{array}\right]=3j(0/25)$