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امتحان هماهنگ کشوری خرداد 1403

<span class="d-inline-block ltr" data-lexical-equation="XGJlZ2lue21hdHJpeH0KICAgXCxcLFwsXCxcLFxjYW5jZWx7Mnt7eH1eezJ9fX0tN3gtMTVcbGVmdHwgXGRmcmFje3gtNX17MngrM30gXHJpZ2h0LiAgXFwKICAgXHVuZGVybGluZXstKFxjYW5jZWx7Mnt7eH1eezJ9fX0tMTB4KVwsXCxcLFwsXCxcLFwsXCx9XCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCwgIFxcCiAgIFwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCwzeC0xNVwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLFwsXCxcLCAgXFwKICAgXHVuZGVybGluZXstKDN4LTE1KX0gIFxcCiAgIDAgIFxcClxlbmR7bWF0cml4fQ==" data-lexical-inline="true">2x2<svg width="100%" height="0.8141em"><line x1="0" y1="100%" x2="100%" y2="0" stroke-width="0.046em"></line></svg>−7x−15<svg width="0.333em" height="2.400em" viewBox="0 0 333 2400"><path d="M145 15 v585 v1200 v585 c2.667,10,9.667,15,21,15
c10,0,16.667,-5,20,-15 v-585 v-1200 v-585 c-2.667,-10,-9.667,-15,-21,-15
c-10,0,-16.667,5,-20,15z M188 15 H145 v585 v1200 v585 h43z"></path></svg>​2x+3x−5​−(2x2<svg width="100%" height="0.8141em"><line x1="0" y1="100%" x2="100%" y2="0" stroke-width="0.046em"></line></svg>−10x)​3x−15−(3x−15)​0​

تقسیم زیر را انجام دهید. (1/25)2x2−7x−15<svg width="0.333em" height="2.400em" viewBox="0 0 333 2400"><path d="M145 15 v585 v1200 v585 c2.667,10,9.667,15,21,15
c10,0,16.667,-5,20,-15 v-585 v-1200 v-585 c-2.667,-10,-9.667,-15,-21,-15
c-10,0,-16.667,5,-20,15z M188 15 H145 v585 v1200 v585 h43z"></path></svg>​x−5​

حل تشریحی سوال شماره 15 ریاضی

امتحان هماهنگ کشوری خرداد 1403

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