حل تشریحی سوال شماره 233 ریاضی و آمار 3 انسانی

الف)

${\left(\frac{a^{\frac{-1}{3}}}{a^{\frac{-1}{6}}}\right)}^{-6}=\frac{a^2}{a^1}=a$

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روش دوم:

${(a^{-\frac{1}{3}(-\frac{1}{6})})}^{-6}={(a^{-\frac{1}{6}})}^{-6}=a$

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ب)

${(3)}^{\frac{1}{2}}\times {(12)}^{\frac{1}{2}}\times {(0/7)}^0={(3\times 12)}^{\frac{1}{2}}\times 1={(36)}^{\frac{1}{2}}=6$

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